Setting the status code

Dennis Jacobfeuerborn dennisml at conversis.de
Tue Aug 6 22:19:29 UTC 2013


On 06.08.2013 13:31, Richard Kearsley wrote:
> On 06/08/13 04:02, Dennis Jacobfeuerborn wrote:
>
>> Since I determine the reason for the denied access in lua a way to do
>> it there would also help. I already tried "nginx.status = 403"
>> followed by a "nginx.exec('/reason1')" but while the right page is
>> display the status code returned gets reset to 200.
>
>
> Hi
> You can do it in lua.. you need to do it in the header filter stage
> I'm doing something similar but probably not exactly the same
> Hopefully example helps (untested):
>
>          set $status_code "";
>          location /
>          {
>              access_by_lua '
>                  -- your lua script here etc...
>                  -- if (an error happened) then
>                      ngx.var.status_code = "403"
>                      ngx.exec("/error/403.html")
>                  -- end
>                  ';
>          }
>
>          location /error
>          {
>              root html/error;
>              header_filter_by_lua '
>                  if ngx.var.status_code ~= "" then
>                      ngx.status = ngx.var.status_code
>                  end
>              ';
>          }

That did the trick, thanks!

What I basically wound up doing is:

     location /error {
         root   /var/www/html;
         header_filter_by_lua '
             ngx.status = 503
         ';
     }

Kind of awkward to be forced to use Lua just for this. There should be a 
"status_code <code>" directive to make this possible without requiring 
the Lua module.

Regards,
   Dennis



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